## Book I. Proposition47Problems 1. a) State the hypothesis of Proposition 47. To see the answer, pass your mouse over the colored area. Squares are drawn on each side of a right triangle. 2. b) State the conclusion.
The square drawn on the side opposite the right angle 2. c) Practice Proposition 47. 2. a) Draw two squares. Now draw a third square equal to the two of 2. b) Draw a square which is equal to the sum of three squares. 3. ABCD is a circle with center E, and EF, EG are perpendiculars to
the 3. a) Prove that the squares on AF, FE together are equal to the
squares 3. b) If AF is less than DG, will FE be greater than, equal to, or less 4. Prove this special case of side-side-angle. If in two right triangles the hypotenuse and a side of one 4. (Hint: Proposition 34, Problem 10.) 5. If the square drawn on one side of a triangle is equal to the squares In triangle ABC, let the square drawn on BC be equal to the squares drawn on the sides CA, AB; From the point A, draw AD at right angles to CA; (The proof will now show that triangles CAD, CAB are congruent; hence angle CAB is also a right angle. The student should justify each statement.) Then, because AD is equal to BA, the square on AD is equal to the square on BA. I-46, Problem 5a. To each of these join the square on AC. Therefore the squares on AD, AC are equal to the squares on BA, AC. Axiom 2 But because angle CAD is a right angle, Construction And, by hypothesis, the square on CB is equal to the squares on BA, AC. Therefore the square on CD is equal to the square on CB. Axiom 1 Therefore the side CD is equal to the side CB. I-46, Problem 5b. Now, because side DA is equal to side BA, But angle CAD is a right angle; Construction Therefore, Table of Contents | Introduction | Home Please make a donation to keep TheMathPage online. Copyright © 2012 Lawrence Spector Questions or comments? E-mail: themathpage@nyc.rr.com |