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10 INCOMMENSURABLE MAGNITUDES HERE AGAIN IS THE THEOREM of the previous Topic: Straight lines will have a common measure -- they will have the same ratio as natural numbers -- if and only if the squares on them have the same ratio as square numbers. What, then, will be the case if two squares are not in the same ratio as two square numbers? What if one square is twice the size of another?
2 and 1 are not both square numbers. What must we say about the ratio of the sides? The sides do not have the same ratio as two natural numbers We say that those sides are incommensurable. Problem 1. a) If one square is three times the size of another square, are their sides To see the answer, pass your mouse over the colored area. Incommensurable. The squares are in the ratio 3 to 1, and 3 and 1 are not both square numbers. b) If the side of one square is a multiple of one-eighth of an inch, could No. Those sides have no common measure. c) If one side is so many millionths of an inch, could the other side also d) If one side is a multiple of any unit fraction, could the other side also e) Will those sides have the same ratio as two natural numbers? That is, No! f) If one side is a rational number of units, could the other side also be a No. They cannot both be rational, because if they were, they would have a common measure. (Topic 8.) g) Can you express the ratio of those sides? Can you? Problem 2. How will we know when straight lines are incommensurable? The squares on them are not in the same ratio as square numbers. Problem 3. a) If two squares are to one another as 9 is to 20, do their sides have a No. 9 and 20 are not both square numbers. b) If two squares are to one another as 9 is to 25, do their sides have a The smaller side is three fifths of the larger. Problem 4. Let a square be 10 square meters. a) Does that square have a common measure with 1 square meter? Yes. 10 and 1 are natural numbers. b) Will its side have a common measure with 1 meter? No. 10 and 1 are not both square numbers. c) Will its side be a rational number of meters? No. The side has no common measure with 1 meter. Problem 5. a) If one square is four ninths of another square, is its side a fraction of Yes. 4 and 9 are square numbers. b) If one square is four fifths of another square, is its side a fraction of No. 4 and 5 are not both square numbers. Could both sides be a rational number of centimeters? No. Common multiples? When straight lines are commensurable, then if we took multiples of them, they will have common multiples, and in particular they will have a lowest common multiple.
If one line for example is 6 cm and the other 8 cm, then their lowest common multiple will be 24 cm. Since 3 × 8 is 24, and 4 × 6 is 24, that implies that the ratio of those lines is in fact the same as the ratio of two natural numbers, namely 3 to 4. But if we took multiples of two incommensurable magnitudes -- call
them a and b -- then they will never have a common multiple. Because if they did, they would have same ratio as two natural numbers, which they do not Problem 6. Since any two lengths could be measured with a ruler, and we will always get rational numbers, what sense does it make to say that two lengths are incommensurable? Since lengths are continuous, with no units to count, we always have the problem of measuring exactly. Measurement is limited not only by the fineness of the measuring instrument, but also by the fineness of our eyes to see its readings!
do, or do not, have a common measure, we mean as determined logically, not with rulers. Problem 7. a) Again, what is the ratio that natural numbers have to one another? One number is a multiple of the other, a part of it, or parts of it; or a mixture of those. Express the following ratios:
b) Are magnitudes necessarily in the same ratio as natural numbers? No. We cannot always express their relationship in words. c) Therefore, what do we mean by the "ratio" of two magnitudes? ? ? ? The new theory of proportions Incommensurability completely upsets the theory of proportions. For if
the square on AB is twice the square on CD, if they are in the ratio 2 : 1, then the lengths AB, CD are incommensurable; 2 is not a square number. And if the square on EF is also twice the square on GH, then EF, GH are also incommensurable -- yet we expect that whatever relationship AB has to CD, EF will have it to GH. We expect, proportionally, AB is to CD in the same ratio as EF is to GH. But according to the definition of natural numbers being "in the same ratio," that
will make no sense, because AB is not any multiple of CD, any part of it or any parts of it Yet we can see that they have the same relationship. Therefore we must create a new definition of "in the same ratio," one that will be applicable to incommensurable magnitudes. We will not present the new definition here. Seeing the need for it -- namely, the discovery of incommensurables -- is the climax of our present study. Historically, the need for a new definition of "in the same ratio" was mathematics first logical crisis, and it has always marked the beginning of advanced mathematics. Next Topic: Irrational numbers Please make a donation to keep TheMathPage online. Copyright © 2001-2008 Lawrence Spector Questions or comments? E-mail: themathpage@nyc.rr.com |
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