19 ## INVERSE TRIGONOMETRIC FUNCTIONSTHE ANGLES in theoretical work will be in radian measure. Thus if
function of it.
(Topic 13.) Inversely, if we are given that the sin "The sine of what angle is equal to ½?" We could answer:
The algebraic abbreviation for that sentence is:
arcsin It is the Strictly, The inverse of the function
is
Their inverse relation is as follows: arcsin Thus,
Corresponding to each trigonometric function, there is its inverse function. arcsin arccos arctan arccsc arcsec arccot In each one, we are given the Problem 1. To see the answer, pass your mouse over the colored area. a) arctan b) arcsec c) arccos 1 = 0 if and only if 1 = cos 0.
The range of
And so on. For the function They are called the principal values of arcsin
The range, then, of the function
To restrict the Angles whose sines are positive will be 1st quadrant angles, while angle whose sines are negative will fall in the 4th. If fact,
The angle whose sine is − To see that, look here:
sin Another notation for arcsin Problem 2. Evaluate the following in radians. a) sin b) sin c) sin
The range of Similarly, we must restrict the range of
(Topic 15.) For an angle whose tangent is positive, we choose a 1st quadrant angle. For an angle whose tangent is negative, we choose a 4th quadrant angle. Like arcsin (− arctan (−
Problem 3. Evaluate the following.
The range of Example 3. Evaluate arccos ½.
Problem 4. Why is this not true?
An angle whose cosine is negative will fall in the 2nd quadrant, where it will have its smallest absolute value. (Topic 15.) The cosine of a 2nd quadrant angle is the negative of the cosine of its supplement, which is the corresponding acute angle. That implies: An angle θ whose cosine is − arccos (− Therefore,
The range, then, of An angle whose cosine is positive will be a 1st quadrant angle; an angle whose cosine is negative will fall in the 2nd. It will be the supplement of the 1st quadrant angle. Problem 5. Evaluate the following.
The range of In calculus, sin If The only inverse function below in which Again, we restrict the values of The inverse relations If we put
and
then according to the definition of inverse functions (Topic 19 of Precalculus):
sin(arcsin In particular,
By taking the inverse function of both sides, we have extracted, or freed, the argument
Example 4. Solve for
Therefore,
Problem 6. Solve for tan (
Problem 7. Solve for cos
Theorem. If
then the product sec For, if When angle If Therefore, that product is never negative. (This theorem is referenced in the proof of the derivative of Next Topic: Trigonometric identities Please make a donation to keep TheMathPage online. Copyright © 2015 Lawrence Spector Questions or comments? E-mail: themathpage@nyc.rr.com |